errorMessage: Bad handler
Make sure when specifying the handler you use the format [file name].[function name].
For example if you have the function configure_firebox and the python file name is fireboxconfig.py then specify the handler as fireboxconfig.configure_firebox
If you are specifying the name correctly and still getting the error, take a look at your zip file and make sure the python file you are referencing is at the root of the zip file, not in any folders when the code is unzipped.
If you are trying to use the zip function to zip a file into the archive without the directories use the -j switch:
zip -j ./resources/firebox-lambda/fireboxconfig.zip ./resources/firebox-lambda/python/fireboxconfig.py
Also check for any spelling errors in your file or handler name.
In CloudFormation:
FireboxConfigurationLambda:
Type: "AWS::Lambda::Function"
Properties:
Code:
S3Bucket: !ImportValue FireboxPrivateBucket
S3Key: fireboxconfig.zip
Description: Firebox Lambda to Execute CLI Commands
Environment:
Variables:
Test: Value
FunctionName: ConfigureFirebox
Handler: fireboxconfig.configure_firebox
KmsKeyArn: !ImportValue FireboxKmsKeyArn
MemorySize: 128
Role: !ImportValue FireboxLambdaCLIRoleArn
Runtime: python3.6
Timeout: 3
VpcConfig:
SecurityGroupIds:
- !ImportValue FireboxManagementSecurityGroup
SubnetIds:
- !ImportValue FireboxCLISubnet
More:
http://docs.aws.amazon.com/lambda/latest/dg/python-programming-model-handler-types.html
https://github.com/tradichel/FireboxCloudAutomation/blob/master/code/resources/firebox-lambda/lambda.yaml
